{"id":4685,"date":"2023-09-14T11:30:45","date_gmt":"2023-09-14T08:30:45","guid":{"rendered":"https:\/\/blog.inekle.com\/?p=4685"},"modified":"2026-08-25T20:07:48","modified_gmt":"2026-08-25T17:07:48","slug":"280-yildir-cozum-bekleyen-problem-goldbach-hipotezi","status":"publish","type":"post","link":"https:\/\/blog.inekle.com\/280-yildir-cozum-bekleyen-problem-goldbach-hipotezi\/","title":{"rendered":"Goldbach Hipotezi: 280 Y\u0131ll\u0131k Bir Soru"},"content":{"rendered":"\n

Merhaba sevgili inekle Blog Okurlar\u0131. Bug\u00fcne kadar hepimiz az veya \u00e7ok matematik problemleriyle cebelle\u015ftik, kimisini \u00e7\u00f6zd\u00fck kimisini ise yar\u0131da b\u0131rakt\u0131k. Hatta bazen i\u015fin i\u00e7inden dahi \u00e7\u0131kamad\u0131k. Ara s\u0131ra komik cevaplar bulanlar\u0131m\u0131z da mutlaka vard\u0131r, mesela \u00e7ocu\u011fu babadan b\u00fcy\u00fck bulmak gibi. En az\u0131ndan yanl\u0131\u015f bir \u015feyler elde etmek bile hi\u00e7bir \u015fey elde edememekten daha iyidir. Ancak baz\u0131 problemler vard\u0131r ki yanl\u0131\u015f bir \u015feyler elde etmek, do\u011fru bir \u015feyler elde etmekten daha avantajl\u0131 olabilir, en az\u0131ndan asl\u0131nda \u00f6yle gibi g\u00f6r\u00fcnenlerin \u00f6yle olmad\u0131\u011f\u0131n\u0131 anlat\u0131r. \u0130\u015fte tam burada 1742 y\u0131l\u0131nda matematik\u00e7i Christian Goldbach taraf\u0131ndan ortaya at\u0131lan bir problemden bahsetmek istiyorum. Problem Christian Goldbach taraf\u0131ndan 18.y\u00fczy\u0131lda \u015fu ifadelerle ortaya konuldu: 2’den b\u00fcy\u00fck her \u00e7ift say\u0131 iki asal say\u0131n\u0131n toplam\u0131 \u015feklinde yaz\u0131labilir.<\/p>\n\n\n

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Elbette ki bu, k\u00fc\u00e7\u00fck say\u0131lar i\u00e7in ispat\u0131 kolay olan bir problem. \u00d6rne\u011fin: 8 = 5 + 3
28 = 5 + 23
84 = 41 + 43<\/p>\n\n\n\n

Say\u0131lar b\u00fcy\u00fcd\u00fck\u00e7e zorluk seviyesi de do\u011fal olarak artmakta. \u00d6rne\u011fin: 126 = 59 + 67
162 = 79 + 83
186 = 97 + 89<\/p>\n\n\n\n

Say\u0131lar\u0131 biraz daha b\u00fcy\u00fctelim. \u00d6rne\u011fin: 350 = 151 + 199
1302 = 619 + 683
1988 = 997 + 991<\/p>\n\n\n

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\u0130\u015fte bu \u015fekilde y\u00fczy\u0131llar boyunca matematik\u00e7iler bu problemle u\u011fra\u015ft\u0131lar. 1855 y\u0131l\u0131nda Desboves, bu hipotezi 10.000\u2019e kadar olan \u00e7ift say\u0131larda do\u011frulad\u0131. Daha sonra 1940 y\u0131l\u0131nda Pipping 100.000\u2019e kadar olan \u00e7ift say\u0131lar i\u00e7in do\u011fru oldu\u011funu g\u00f6sterdi. Daha sonra \u00fcst s\u0131n\u0131r 1964 y\u0131l\u0131nda teknolojinin de yard\u0131m\u0131yla, bilgisayar sayesinde 33.000.000\u2019a, 1965\u2019te 100.000.000\u2019a; ve son olarak do\u011frulu\u011fu 1980\u2019de 200.000.000\u2019a kadar olan \u00e7ift say\u0131larda ispatland\u0131. 1998 y\u0131l\u0131nda ise Alman matematik\u00e7i J\u00f6rg Richstein, Goldbach\u2019\u0131n varsay\u0131m\u0131n\u0131 400 trilyona kadar olan t\u00fcm \u00e7ift say\u0131larda do\u011frulad\u0131. 16 \u015eubat 2008\u2019de Oliveira e Silva \u00fcst s\u0131n\u0131r\u0131 1,1 kentilyon\u2019a \u00e7\u0131kard\u0131! (yani, 1,1 kentilyon = 1.100.000.000.000.000.000). 2012 y\u0131l\u0131nda ise bu \u00fcst s\u0131n\u0131r teknolojik geli\u015fmeye paralel olarak, makineler yard\u0131m\u0131yla 4 kentilyon\u2019a kadar \u00e7\u0131kar\u0131ld\u0131 ( yani, 4 kentilyon 4.000.000.000.000.000.000).<\/p>\n\n\n

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\"\"<\/a><\/figure>\n<\/div>\n\n\n

\u00dczerinden yakla\u015f\u0131k 280 y\u0131l ge\u00e7mesine ra\u011fmen g\u00fcn\u00fcz\u00fcmde de Goldbach hipotezi do\u011fru mu yanl\u0131\u015f m\u0131 bilinmemekte. Buradaki temel sorunumuz asl\u0131nda sonsuz say\u0131da asal say\u0131n\u0131n ve sonsuz say\u0131da tam say\u0131n\u0131n olmas\u0131nda. San\u0131r\u0131m yanl\u0131\u015f bir \u015feyler elde edilemezse bu problem sonsuza kadar \u00e7\u00f6z\u00fclemeyecektir, \u00e7\u00fcnk\u00fc sonlu olan bizler sonsuz olanlarla u\u011fra\u015famay\u0131z. E\u011fer olur da problemin \u00e7\u00f6z\u00fcm\u00fcne y\u00f6nelik do\u011fru veya yanl\u0131\u015f bir kan\u0131t\u0131n\u0131z varsa tam olarak elde edece\u011finiz \u00f6d\u00fcl miktar\u0131 1.000.000 dolar. Aksi halde bu problem matemati\u011fin \u00e7\u00f6z\u00fclememi\u015f problemleri aras\u0131nda yer almaya devam edecektir.<\/p>\n\n\n\n

Emre Kahraman<\/p>\n\n\n\n

\"\"<\/a><\/figure>\n\n\n\n

14.09.2023<\/p>\n\n\n\n

<\/p>\n","protected":false},"excerpt":{"rendered":"

Merhaba sevgili inekle Blog Okurlar\u0131. Bug\u00fcne kadar hepimiz az veya \u00e7ok matematik problemleriyle cebelle\u015ftik, kimisini \u00e7\u00f6zd\u00fck kimisini ise yar\u0131da b\u0131rakt\u0131k. Hatta bazen\u2026<\/p>\n","protected":false},"author":1,"featured_media":4766,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_inekle_views":9,"footnotes":""},"categories":[88],"tags":[708,22,2317,2316,711,163,42,49,154,2318,686,70,151,685],"class_list":["post-4685","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-veliler-icin","tag-ayt","tag-canli-ders","tag-geeometri","tag-goldbach-hipotezi","tag-lgs","tag-lys-tavsiyeleri","tag-matematik","tag-online-dershane","tag-online-ozel-ders","tag-tezler","tag-tyt","tag-universite-tercih","tag-universiteliden-ozel-ders","tag-yks"],"_links":{"self":[{"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/posts\/4685","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/comments?post=4685"}],"version-history":[{"count":0,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/posts\/4685\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/media\/4766"}],"wp:attachment":[{"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/media?parent=4685"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/categories?post=4685"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/tags?post=4685"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}