{"id":4477,"date":"2023-08-01T11:11:10","date_gmt":"2023-08-01T08:11:10","guid":{"rendered":"https:\/\/blog.inekle.com\/?p=4477"},"modified":"2026-08-25T20:07:51","modified_gmt":"2026-08-25T17:07:51","slug":"matematikci-cocuk-carl-friedrich-gauss","status":"publish","type":"post","link":"https:\/\/blog.inekle.com\/matematikci-cocuk-carl-friedrich-gauss\/","title":{"rendered":"Matematik\u00e7i \u00c7ocuk-Carl Friedrich Gauss"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Hen\u00fcz sekiz ya\u015f\u0131ndaki bu \u00e7ocuk s\u0131n\u0131f arkada\u015flar\u0131na hi\u00e7 benzemiyordu. Bir g\u00fcn s\u0131n\u0131ftaki \u00f6\u011frencilerin g\u00fcr\u00fclt\u00fclerinden b\u0131kan matematik \u00f6\u011fretmeni, g\u00fcn\u00fcm\u00fczde ilk\u00f6\u011fretim ikinci s\u0131n\u0131fa denk gelen \u00f6\u011frencilerini oyalamak i\u00e7in enfes bir y\u00f6ntem bulmu\u015ftu. Tahtan\u0131n ba\u015f\u0131nda, elinde tebe\u015firiyle yazmaya ba\u015flad\u0131: 1+2+3+4+5+6+7\u2026+100. Bu toplama i\u015flemi s\u0131n\u0131ftaki \u00f6\u011frencilerin bilgi seviyesinin \u00e7ok \u00e7ok \u00fczerindeydi ki s\u0131n\u0131ftaki \u00f6\u011frenciler \u00e7aresiz olarak en soldan iki\u015ferli iki\u015ferli toplamaya ba\u015flad\u0131.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><a href=\"https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-86.png\"><img loading=\"lazy\" decoding=\"async\" width=\"780\" height=\"470\" src=\"https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-86.png\" alt=\"\" class=\"wp-image-4478\" srcset=\"https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-86.png 780w, https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-86-300x181.png 300w, https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-86-768x463.png 768w\" sizes=\"auto, (max-width: 780px) 100vw, 780px\" \/><\/a><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">1+2 = 3<br>3 + 3 = 6<br>6 + 4 = 10<br>Say\u0131lar b\u00fcy\u00fcd\u00fck\u00e7e toplama i\u015flemi zaman al\u0131yor hatta i\u015fin i\u00e7inden \u00e7\u0131k\u0131lamayacak hale geliyordu ama ba\u015fka \u00e7are de yoktu, ta ki Gauss ortaya \u00e7\u0131kana kadar. \u00d6\u011frenciler git gide zorla\u015fan toplama i\u015flemleriyle me\u015fgulken Gauss say\u0131lar\u0131 dikkatle inceliyor, klasik rutinlerden ziyade daha ba\u015fka bir \u015feyler ar\u0131yor, ke\u015ffetmeye \u00e7al\u0131\u015f\u0131yordu. Bu s\u0131rada s\u0131n\u0131f\u0131 susturmay\u0131 ba\u015faran \u00f6\u011fretmen, masas\u0131na ge\u00e7mi\u015f ve cebinden \u00e7\u0131kard\u0131\u011f\u0131 elmay\u0131 soymaya koyulmu\u015f, keyif yapmaya haz\u0131rlan\u0131yordu. K\u0131sa bir s\u00fcre sonra bir \u00f6\u011frenci sorunun cevab\u0131n\u0131 elindeki k\u00e2\u011f\u0131da yaz\u0131p aya\u011fa kalkt\u0131, bu Carl Friedrich Gauss idi. S\u0131n\u0131f arkada\u015flar\u0131n\u0131n \u015fa\u015fk\u0131n bak\u0131\u015flar\u0131 aras\u0131nda \u00f6\u011fretmeninin yan\u0131na yakla\u015fan Gauss, k\u00e2\u011f\u0131d\u0131 \u00f6\u011fretmenine uzatt\u0131. K\u00e2\u011f\u0131tta 5050 yaz\u0131yordu, \u015fa\u015fk\u0131n bir bak\u0131\u015f atan \u00f6\u011fretmeni Gauss\u2019a bu cevab\u0131 nas\u0131l buldu\u011funu sordu. Toplama i\u015flemindeki say\u0131lar\u0131 inceleyen Gauss, harika bir \u015fey ke\u015ffetmi\u015fti. Toplama i\u015flemindeki say\u0131lar\u0131n bir ba\u015f\u0131ndan bir de sonundan say\u0131lar\u0131 al\u0131p toplad\u0131\u011f\u0131nda hep ayn\u0131 sonucu elde etti\u011fini fark etti.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><a href=\"https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-87.png\"><img loading=\"lazy\" decoding=\"async\" width=\"964\" height=\"528\" src=\"https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-87.png\" alt=\"\" class=\"wp-image-4479\" srcset=\"https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-87.png 964w, https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-87-300x164.png 300w, https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-87-768x421.png 768w\" sizes=\"auto, (max-width: 964px) 100vw, 964px\" \/><\/a><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\"><br>1 + 100 = 101<br>2 + 99 = 101<br>3 + 98 = 101<br>Bu \u015fekilde toplama i\u015fleminde ne kadar say\u0131 varsa o say\u0131n\u0131n yar\u0131s\u0131 kadar ilerleyebilirdi. 100 tane say\u0131 vard\u0131 ki toplama i\u015flemi art\u0131k 100\/2 = 50 tane 101\u2019in ne oldu\u011funu bulmaya indirgenmi\u015fti. O da 50.101 = 5050 sonucunu veriyordu. \u0130\u015fte hen\u00fcz sekiz ya\u015f\u0131ndayken bunu ke\u015ffeden Gauss, asl\u0131nda bize verilenlerle yetinmememiz gerekti\u011finin s\u00f6zl\u00fc olmasa bile matematiksel olarak ispat\u0131n\u0131 yap\u0131yordu belki de.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Emre Kahraman<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><a href=\"https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-88.png\"><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"150\" src=\"https:\/\/blog.inekle.com\/wp-content\/uploads\/2023\/07\/image-88.png\" alt=\"\" class=\"wp-image-4480\"\/><\/a><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">01.08.2023<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Hen\u00fcz sekiz ya\u015f\u0131ndaki bu \u00e7ocuk s\u0131n\u0131f arkada\u015flar\u0131na hi\u00e7 benzemiyordu. Bir g\u00fcn s\u0131n\u0131ftaki \u00f6\u011frencilerin g\u00fcr\u00fclt\u00fclerinden b\u0131kan matematik \u00f6\u011fretmeni, g\u00fcn\u00fcm\u00fczde ilk\u00f6\u011fretim ikinci s\u0131n\u0131fa denk\u2026<\/p>\n","protected":false},"author":1,"featured_media":4566,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_inekle_views":0,"footnotes":""},"categories":[380],"tags":[708,22,2247,711,163,49,154,686,70,151,2246,685],"class_list":["post-4477","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-ogrenciler-soruyor","tag-ayt","tag-canli-ders","tag-carl-friedrich-gauss","tag-lgs","tag-lys-tavsiyeleri","tag-online-dershane","tag-online-ozel-ders","tag-tyt","tag-universite-tercih","tag-universiteliden-ozel-ders","tag-unlu-matematikci","tag-yks"],"_links":{"self":[{"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/posts\/4477","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/comments?post=4477"}],"version-history":[{"count":1,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/posts\/4477\/revisions"}],"predecessor-version":[{"id":11192,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/posts\/4477\/revisions\/11192"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/media\/4566"}],"wp:attachment":[{"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/media?parent=4477"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/categories?post=4477"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.inekle.com\/wp-json\/wp\/v2\/tags?post=4477"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}